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Aneli [31]
3 years ago
11

The percent decrease of an item that dropped in price from $50 to $43 is​

Mathematics
2 answers:
Ber [7]3 years ago
7 0

Answer:

14%

Step-by-step explanation:

decreased price = 50 - 43 =$7

decreased percent=\frac{7}{50}*100=7*2=14

frez [133]3 years ago
5 0

Answer:

14%

Step-by-step explanation:

The item dropped from $50 to $43 .

Therefore,

Decrease = $50 - $43

= $7

To get the % decrease, divide the decrease by the initial price and multiply the result by 100%

That’s

$7/$50 x 100%

$0.14 x 100%

= 14%

The price of the item decreased by 14%

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1. The teacher assigns homework after 7/10
asambeis [7]

Answer:

B) Likely

Step-by-step explanation:

Unlikely = < 50%

Likely = > 50%

Certain = 100%

Equally likely = 50%

8 0
3 years ago
In trapezoid $PQRS,$ $\overline{PQ} \parallel \overline{RS}$. Let $X$ be the intersection of diagonals $\overline{PR}$ and $\ove
jeyben [28]

The area of the trapezoidal comes out to be 125 square units.

<h3>What is trapezoidal?</h3>

A four-sided shape called a trapezoid has one pair of parallel sides. It fundamentally resembles a square, rectangle, or parallelogram in two dimensions.

Now, according to the question;

If a trapezoid PQRS of parallel sides PQ & RS has always been divided into 4 triangles by it's own diagonals PR and QS, which intersect at X,

Then, the area for triangle PSX equals which of triangle QRX, as well as the product of triangle PSX but also triangle QRX equals the same of triangle PQX & triangle RSX.

Let area of the triangle PSX is A₁

Let area of the triangle QRX is A₂

Let area of the triangle PQX is A₃

Let area of the triangle RSX is A₄

Then,

A₁ × A₂ = A₃ × A₄

As A₁ = A₂

The,

A₁² = A₃ × A₄

The areas for the triangles;

A₃  = 20 square units

A₄ = 45 square units.

Substitute the values;

A₁² = 20 × 45

      = 900

A₁ = 30

Thus, A₁ = A₂ = 30 square units.

The entire area of the trapezium is;

= A₁ + A₂ + A₃ + A₄

= 30 + 30 + 20 + 45

= 125

Therefore, the complete area of the trapezium PQRS is 125 square units.

To know more about the trapezoidal, here

brainly.com/question/1410008

#SPJ4

The correct question is-

In trapezoid PQRS, PQ is parallel to RS. Let X be the intersection of diagonals PR and QS. The area of triangle PQX is 20 and the area of triangle RSX is 45. Find the area of trapezoid PQRS.

4 0
1 year ago
I need to know how to solve this equation?
cestrela7 [59]
Your picture shows the first step: use the distributive property to eliminate parentheses.
  5*7 -5*x = 2*x -3
Now, you have an equation with a constant and an x-term on each side. I like to pick the x-term with the smallest (most-negative) coefficient and add its opposite to the equation.

Adding 5x, we have
  35 = 7x -3
Adding 3 will get the x-term on one side and the constant on the other
  38 = 7x
Now, we divide by the coefficient of x
  38/7 = x = 5 3/7

This is the correct answer, even though it is not an integer.

_____
Check
  5(7 -(5 3/7)) = 2(5 3/7) -3 . . . . substitute for x in the original equation
  5(1 4/7) = 10 6/7 -3 . . . . . . . . . evaluate the parentheses on the left, do the multiplication on the right
  5 20/7 = 7 6/7 . . . . . . . . . . . . do the multiplicaton on the left, the subtraction on the right
  5 +2 6/7 = 7 6/7 . . . . . . . . . . . rewrite 20/7, realize 5+2=7. true
8 0
4 years ago
Please show me the steps of doing this question if you know how, ty.
dolphi86 [110]

The arc length is the product of the angle measure in radians and the radius.

... s = r·θ

So, the angle in radians is the ratio of arc length to radius.

... θ = s/r

To convert from radians to degrees, multiply by the conversion factor 180°/(π radians).

... y = s/r·(180°/π)

Then the angle is between

... 15/20·180/π ≈ 42.97

and

... 16/20·180/π ≈ 45.84

Suitable integers in this range are 43, 44, and 45.

One possible integer value of y is 44.

7 0
3 years ago
Express each x in terms of y:<br>1. 2x - 3 = y<br><br>2. 2 + 2x -1 = 4y<br><br>3. 2A + 4x + 3B = 10​
jeka57 [31]

Answer:

1/2y+3/2

2y+-1/2

-3/2b-2x+5

Step-by-step explanation:

4 0
3 years ago
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