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3 years ago

795.800.913.789

Mathematics

1 answer:

yulyashka [42]3 years ago

4 0

Answer:

seven hundred ninety-five billion eight hundred million nine hundred thirteen thousand seven hundred eighty-nine

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For a class activity, your group has been assigned the task of generating a quiz question that requires use of the formula for c

soldier1979 [14.2K]

Answer: P(A and B) is greater than P(A)

P(A and B) should be smaller than P(A).

Step-by-step explanation:

Given : P(A and B) = 0.40

P(A) = 0.20

Using the given formula of the conditional probability will be

$P(B|A)=\dfrac{\text{P(A and B)}}{P(A)}\\\\=\dfrac{0.40}{0.20}=2$

But we know that the probability of any event cannot be more than 1.

Also, the probability of the intersection must be less than the probability of individual event.

Thus , in the given question P(A and B) must be smaller than P(A).

3 0

2 years ago

What size bag of fertilizer should the jamisons buy?

vredina [299]

Where is the rest of the question

5 0

2 years ago

The Mississippi River flows at a rate of 16,790 cubic meters per second. Choose the best approximation of the flow rate of the M

tatiyna

Answer:

B, 2(10^4)

Step-by-step explanation:

2(10^3)= 2000

2(10^4)= 20000

2(10^4) Is closer to 16790 than 2(10^3)

8 0

3 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago

Wright the ratio 4.5 : 2.35 in the form n : 1

sergeinik [125]

Answer:

$\frac{9}{47}: 1$

Step-by-step explanation:

you can divide both sides by 2.35 to get the right side to be 1:

$4.5: 2.35\\\frac{9}{47}: 1$

6 0

2 years ago