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Aleks04 [339]
3 years ago
8

Recycling Center A processes aluminum at a rate of 100 pounds per hour, while Recycling Center B processes aluminum at a rate of

2 tons per week. Assuming that both centers operate all day every day, which center processes aluminum faster, and why?
A:Recycling Center A processes aluminum faster; Recycling Center B’s rate is about 12 pounds per hour.
B:Recycling Center A processes aluminum faster; Recycling Center B’s rate is about 24 pounds per hour.
C:Recycling Center B processes aluminum faster; its rate is about 120 pounds per hour.
D:Recycling Center B processes aluminum faster; its rate is about 240 pounds per hour.
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0
<span>Correct answer: B
The first thing to be done is to convert the 2 tons into pounds.
1 pound is equal to 0.0005 tons (US). So, 2 tons divided by 0.0005 will give us the aluminium pounds per week that are processed by the Recycling Centre B.
</span>\frac{2}{0.0005}=4000
<span>Recycling Centre B processes 4000 pounds/week. In order to compare to Recycling Centre A, we need to find the rate in pounds per hour. To do so divide the 4000 pounds by 168 (24</span>×7 = number of hours in a week).
\frac{4000}{168}≈23.8
The Recycling Centre B processes about 23.8 pounds/hour whereas the Recycling Centre A processes 100pounds/hour.
ikadub [295]3 years ago
3 0
C: Recycling center B processes aluminum faster; It’s rate is About 120 Pounds per hour
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Answer:

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Step-by-step explanation:Solution:

step 1 Address the formula, input parameters & values.

Input parameters & values:

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You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
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a. See attachment for the labelled diagram

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c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

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sin 10 = 875/CA

CA = 875/sin 10

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CB = hypotenuse

∅ = 8°

Opposite = 875 m

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CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

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lilavasa [31]

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