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3 years ago

∠2 and ∠6 can be classified as:

Mathematics

2 answers:

aleksklad [387]3 years ago

8 0

Answer:

Corresponding angles

Step-by-step explanation:

Corresponding angles are angles that are on the same side of the transversal ( intersecting lines ) which are congruent ( equal to each other )

Angles 2 and 6 are congruent and are on the same side of the transversal

Lilit [14]3 years ago

6 0

Answer:

A. corresponding angles

Step-by-step explanation:

2 and 6 are on the same side of the transversal and in the corresponding position ( same location) with respect to the parallel lines

This makes the corresponding angles

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There were 296296 tickets purchased for a major league baseball game. The general admissiongeneral admission tickets cost $6.50

VMariaS [17]

Answer:

The general admission ticket number is 160 and the upper box ticket number is 136

Step-by-step explanation:

In this case we can solve it using a 2x2 system of equations, like this:

let x be general admission tickets number

let y be upper box tickets number

So:

6.5 * x + 10 * y = 2400

x + y = 296 => x = 296 - y

Replacing, we are left with that:

6.5 * (296 - y) + 10 * y = 2400

1924 - 6.5 * y + 10 * y = 2400

10 * y - 6.5 * y = 2400 - 1924

3.5 * y = 476

y = 476 / 3.5

y = 136

Now to calculate x:

x = 296 - 136

x = 160

The general admission ticket number is 160 and the upper box ticket number is 136

4 0

3 years ago

A function f has the property that f(x-y)=f(x)/(y) f(y) does not equal zero if f (8)=256and f(5)=32 what is the value of f(3)

Dvinal [7]

Answer:

shdhhsjsjkalaixhxjalos

3 0

2 years ago

How do I subtract decimals from whole numbers?

Gekata [30.6K]

Answer:

Just use long subtraction by expanding the decimal places of the whole number. This is done by adding a point, and enough zeros to it to match the number of decimal digits in the other number (digits after the decimal point).

12345678

i.e: 5 - 2.48374827, 2.48374827 has 8 decimal digits, so add 8 zeros after the point.

1 1 1 1 1 1 1

5.00000000

2.48374827

_______________

2.51625173

7 + 3 = 10, 7 + 2 + 1 = 10, 8 + 1 + 1= 10, 5 + 4 + 1 = 10, 2 + 7 + 1 = 10, 3 + 6 + 1 = 10, 1 + 8 + 1 = 10, 5 + 4 + 1 = 10, 2 + 2 + 1 = 5 : 5.00000000

This is basically borrowing a group of 10s which are the same as 1s in the next decimal place up.

For each digit except the first to the right, let 10 subtract that number from it and minus 1 since the 1 is carried over.

7 0

3 years ago

It takes 1 1/2 hours to fill 1/2 of a tank how long will it take to fill 2 tanks completely

Likurg_2 [28]

Answer:

Step-by-step explanation:

hope this helps

4 0

2 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

1 year ago