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almond37 [142]
3 years ago
9

Determine the solution set of each equation

Mathematics
2 answers:
Flauer [41]3 years ago
5 0

Answer:

weak in maths sorry I cannot give answer

maks197457 [2]3 years ago
3 0

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Or

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Or

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

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Answer:

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Step-by-step explanation:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

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Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

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216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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