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2 years ago

Solve for m m + k ÷ h = w Literal Equations

Mathematics

1 answer:

SIZIF [17.4K]2 years ago

8 0

Answer:

m+k=hw

m=hw-m

always conside BODMAS rule and subject

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What is the expression using GCF of 2+8

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What is the expression using GCF of 2+8

= 2(1+4)
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3 years ago

A store had 25%off sale on coats with this discount

AleksandrR [38]

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3 years ago

A triangle with sides of lengths 9,22 and 24 is a right triangle True or false

Dmitry [639]

Answer:

False

Step-by-step explanation:

If the triangle is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

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3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$