From the information given, the rotated triangle is same as the original triangle. This is because, vertices of the rotation remain at the origin - (0,0).
<h3>What is the proof the above?</h3>
Notice that the question states: △A'B'C' is the image of △ABC. Given that the △ without primes is the original and the one with primes depict the rotated triangle,
under a rotation about the origin, (0,0) (0,0) (0, 0), indicating no movement,
△A'B'C' is in the same position with △ABC.
Learn more about rotation at:
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Answer:
135°
Step-by-step explanation:
Using S = rA, where S is arc length, r is radius and A is angle(in radians).
Comparing:
=> 12 = 16A
=> 12/16 = A
=> 3/4 = A
Required radian is 3/4 which is 3/4 * 180° = 135°
Base = 12÷2
= 6
slant height = a
a^2 = 6^2 + 8^2
a^2 = 100
a = 10 cm
Answer:
Step-by-step explanation:
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Answer:
= −31/4
(Decimal: -7.75)
Step-by-step explanation:
