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klio [65]
4 years ago
11

Pls help asap Its due in 10 min pls help

Mathematics
1 answer:
solong [7]4 years ago
6 0
The answer is B, Decrease of 72.
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For each of the following studies, say whether you would use a t test for dependent means or a t test for independent means.
Shtirlitz [24]

Answer:

1. T test for independent means

2. T test for dependent means

3. T test for dependent means

Step-by-step explanation:

In number 1, the two groups are unrelated. The first group has 25 subjects and they're all unemployed. The second group has 24 subjects and their employment status is not stated and might not be the same all through. Also, the first group is receiving a new type of job skills program while the second group is taking the standard job skills program.

- The groups in the experiment are unrelated

- The tests in the research are unrelated

- The purpose of the research is unreasonable - the researcher seeks to measure how well all 49 subjects perform on 'a' job skills test! No comparison between the scores or mean scores of the two groups.

In number 2, the researcher uses the same subjects and also measures the same variable but twice. This is a good example of a study where the t test for dependent means can be taken. Same applies in case 3.

5 0
3 years ago
Will someone help me with all of these, I have the answers but I’m trying check them.This is a practice assignment btw.
Ipatiy [6.2K]

We will look at the process of solving literal equations for a particular variable ( x ).

A literal equation is usually categorized by a myraid of constants that are crucial to the process which is being modeled. We solve such equation in terms of a controlling variable ( that we can choose to alter our process ).

For the following literal equations ( x ) will be the subject of variability.

3\cdot(bx\text{ - 2ab ) = }b\cdot(x-7a)\text{ + 3ab}

Whenever we have algebraic expressions we always refer to the rule of ( PEMDAS ).

Step 1: Solve the Parenthesis

We will solve for all the parenthesis in the equation given and write down the result:

3bx\text{ - 6ab = bx - 7ab + 3ab }

Step 2: Highlight and combine the like terms

All like terms are classified on the basis of their constants ( a and b ) and variable ( x ) attached. We will highlight all the like terms and take simplify them on either side of the " = " sign:

\begin{gathered} 3bx\text{ }\text{\textcolor{#FF7968}{- 6ab}}\text{ = bx }\text{\textcolor{#FF7968}{-7ab}}\text{ }\text{\textcolor{#FF7968}{+ 3ab}} \\ 3bx\text{ - bx = 2ab} \end{gathered}

We combined three like terms ( -6ab , -7ab , and 3ab ).

Step 3: Factorize and simplify the equation

Now we will look for any constant that is present in all the terms throughout the equation. We see that constant ( b ) is common in all the terms. Hence, we will factor ( b ) out and cancel it out from each side of the " = " sign as follows:

\begin{gathered} b\cdot(3x\text{ - x ) = b}\cdot(2a) \\ \textcolor{#FF7968}{2x}\text{\textcolor{#FF7968}{ = 2a}} \end{gathered}

Step 4: Solve for the variable ( x )

We are left with a simple expression that relates the constant ( a ) and variable ( x ). We can go ahead and solve for the above:

\begin{gathered} x\text{ = }\frac{2a}{2} \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ = a}} \end{gathered}

5 0
1 year ago
ASAP HELP... I DONT UNDERSTAND.......
daser333 [38]

Answer:

8 is answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
It’s really urgent if you’re not sure please don’t answer I tried solving it like thousands of times. I need the answer to #3
mr Goodwill [35]
Ok so how you do it is on the left nearest to the example number line the compound equality would be x then “<“ this sign with the line under it, then “-3”. For the right side you would put “x > 2” respond if you have any questions
5 0
3 years ago
Braden is coaching a youth soccer team, which has eight players. At the end of a tied game, Braden's team must go into a shootou
cupoosta [38]

Randomly select a chip from a bucket containing eight chips, whick are each uniquely labeled with each child's name

8 0
4 years ago
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