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avanturin [10]
3 years ago
14

A cylindrical hole is drilled into a piece of wood. The radius of the hole is 8 millimeters less than the height, x, of the hole

. If 1,024π cubic millimeters of material was removed to make the hole, the equation x3 + x2 + x − 1,024 = 0 can be used to find that the height of the hole is millimeters.
Mathematics
1 answer:
ipn [44]3 years ago
7 0

Using the solver function of the calculator, we can find the roots of the polynomial.

x1 = 9.72484

x2 = −5.36242+8.74882i

x3 = −5.36242−8.74882i

<span>   Since dimension cannot be imaginary, therefore the height of the cylindrical hole is 9.72 mm. Calculating for radius r: r = 9.72 mm – 8 mm r = 1.72 mm   The volume of cylinder is given as: V = π r^2 h V = π (1.72)^2 (9.72) <span>V = 90.34 mm^3</span></span>
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Murljashka [212]

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Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

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2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

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3 years ago
A brother and a sister are in the same math class. There are 8 boys and 10 girls in the class. One boy and one girl are randomly
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3 years ago
If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b
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Answer:

a=-23\\\\b=28

Step-by-step explanation:

Let's start by using distributive multiplication:

(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd

So:

(5x-4)(3x+7)=15x^2+35x-12x-28\\\\

Grouping like terms:

15x^2 +(35x-12x)-28\\\\15x^2+23x-28

Now, 15x^2+23x-28 is equal to:

15x^2-ax-b

In this sense:

15x^2+23x-28=15x^2-ax-b

In order to satisfied the equality:

23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)

Hence, from (1), let's solve for a:

23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23

And from (2), let's solve for b:

-28=-b\\\\b=28

Let's verify the result evaluating the values of a and b into the original equation:

(5x-4)(3x+7)=15x^2+23x-28=15x^2 -ax -b\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 -(-23)x -(28)\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 +23x -28

As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

3 0
3 years ago
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