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sukhopar [10]
3 years ago
14

A coin is flipped twice. True or false, the unconditional probability of getting tails on the secondflip is the same as the cond

itional probability of getting tails on the second flip given that the firstflip came up heads
Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:  Given statement is TRUE.

Step-by-step explanation:

Let E and F represents  the events of getting tails on first flip and second flip respectively.

Then, we have

P(E)=\dfrac{1}{2},\\\\\\P(F)=\dfrac{1}{2}.

So, the unconditional probability of getting tails on the second flip is given by

P(F)=\dfrac{1}{2}.

And,  the conditional probability of getting tails on the second flip given that the first flip came up head is given by

P(F/E')=\dfrac{P(F\cap E')}{P(E')}=\dfrac{\frac{1}{4}}{1-\frac{1}{2}}=\dfrac{\frac{1}{4}}{\frac{1}{2}}=\dfrac{1}{2}.

Therefore, we get

P(F)=P(F/E').

Thus, the unconditional probability of getting tails on the second flip is the same as the conditional probability of getting tails on the second flip given that the first flip came up head.

Given statement is TRUE.

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alexdok [17]

Answer:

im not great at math but i believe the answer is  24mm^2

Step-by-step explanation:

triangle area formula- (B*H)/2

large triangle:

6+4+2=12

H=12

B=5

5*12=60

60/2=30

small trangle:

4*3=12

12/2=6

30-6=24

therefore answer should be 24mm^2

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3 years ago
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How many solutions does the nonlinear system of equations graphed below
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Answer:

D. zero

Step-by-step explanation:

Since the graphs do not intersect, there are zero solutions.

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3 years ago
The mean throwing distance of a football for a Marco, a high school freshman quarterback, is 40 yards, with a standard deviation
Phoenix [80]

Answer:

a) One-tailed t-test about a mean.

b) The null hypothesis would be that there is no significant evidence to conclude that the adjusted grip leads to more distance on the thrown ball.

While the alternative hypothesis is that there is significant evidence to conclude that the adjusted grip leads to more distance on the thrown ball.

Mathematically,

The null hypothesis is represented as

H₀: μ ≤ 40 yards

The alternative hypothesis is given as

Hₐ: μ > 40 yards

c) p-value = 0.00621

d) The graph is presented in the attached image. The p-value obtained is less than the significance level at which the test was performed, hence, we accept the alternative hypothesis and say that there is significant evidence to conclude that the adjusted grip leads to more distance on the thrown ball.

Step-by-step explanation:

a) This test checks if the adjusted grip leads to more distance than before on the ball throws.

So, it is a one tailed test (testing only in one direction), a t-test about a mean.

b) For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

Since this question aims to test if adjusting the grip leads to more distance on the ball thrown.

The null hypothesis would be that there is no significant evidence to conclude that the adjusted grip leads to more distance on the thrown ball. That is, The adjusted grip leads to a distance lesser than or equal to the previous distance on the thrown ball.

While the alternative hypothesis is that there is significant evidence to conclude that the adjusted grip leads to more distance on the thrown ball.

Mathematically,

The null hypothesis is represented as

H₀: μ ≤ 40 yards

The alternative hypothesis is given as

Hₐ: μ > 40 yards

c) To do this test, we will use the z-distribution because there is information on the population standard deviation.

So, we compute the test statistic

z = (x - μ₀)/σ

x = 45 yards

μ₀ = 40 yards

σ = standard deviation = 2 yards

z = (45 - 40)/2 = 2.50

The p-value for a one-tailed test for z-test statistic of 2.50 is 0.00621

d) The sketch of the graph is presented in the attached image.

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.00621

0.00621 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis & accept the alternative hypothesis and say that there is enough evidence to conclude that the adjusted grip leads to more distance on the thrown ball.

Hope this Helps!!!

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