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AlekseyPX
3 years ago
9

Please help with this question

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

you can used the give answer app and will tell you everything

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Rewrite 4n^2+2n as a factorial.
Shkiper50 [21]

Answer:

4n²+2n as a factorial is given as:

= (2n+1)!/(2n-1)!

Step-by-step explanation:

We are given an expression which has to be converted into factorial form.

The expression is as follows:

4n^{2} + 2n\\ = 2n(2n+1)\\ = (2n+1)2n\\

Now we know that 2n+1 and 2n differs by '1' and the next smaller term is '2n-1'.

Hence, multiplying and dividing by '(2n-1)!'; we get:

= ((2n+1)(2n)(2n-1)!)/(2n-1)!

we know that x(x-1)(x-2)! = x!, so:

= (2n+1)!/(2n-1)!

4 0
3 years ago
Who do you simplify 10/12
Airida [17]

Answer:

5/6

Step-by-step explanation:

reduce by a number that goes in both numbers like 2

10/2= 5

12/2 = 6

5/6 is the reduce fraction

3 0
3 years ago
Read 2 more answers
Select all true statements
Vilka [71]

Answer:

d and c

Step-by-step explanation:

triangle: base times height divided by 2

(6)(5)/2=15

Rectangle: A=wl

(3)(5)=15

3 0
3 years ago
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
bearhunter [10]

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 5500

H1 : μ > 5500

The test statistic assume normal distribution :

Test statistic :

(Xbar - μ) ÷ s/sqrt(n)

(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143

Pvalue from test statistic :

The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083

α = 0.05

Since ;

Pvalue < α

0.025083 < 0.05 ; Reject H0

The confidence interval :

Xbar ± Tcritical * s/sqrt(n)

Tcritical at 95% = 1.761 ;

margin of error = 1.761 * 226.1/sqrt(15) = 102.805

Lower boundary : (5625.1 - 102.805) = 5522.295

(5522.295 ; ∞)

The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500

4 0
3 years ago
What is the one shape of cross-section we could create by slicing the cylinder parallel to its base?
Temka [501]

Answer:circle

Step-by-step explanation:

I got it right on the test.

5 0
3 years ago
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