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wel
3 years ago
9

A car travels at a constant speed.

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

<h3>Given</h3>
  • Distance is 142.2 m, correct to 1 decimal place
  • Time is 7 seconds,  correct to nearest second
<h3>To find:</h3>
  • Upper bound for the speed
<h3>Solution </h3>

<em>Upper bound for the speed  = upper bound for distance/lower bound for time</em>

  • Upper bound for distance = 142.25 m  (added 0.1/5 = 0.05)
  • Lower bound for time = 6.5 seconds  (subtracted 1/2 = 0.5)

<u>Then, the speed is:</u>

  • 142.25/6.5 = 21.88 m/s
  • 21.88 = 21.9 m/s correct to 1 decimal place
  • 21.88 = 22 m/s correct to nearest m/s

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4 • (6 – 4) 2 ÷ 2
Dmitry_Shevchenko [17]

Answer:

Cary is wrong

Step-by-step explanation:

4* (6-4)= 4* 2=8

I think it is saying (8*2) divided by to, which in that case is 8,

but if it is asking 8 (2/2) then that would also be 8 I believe. I really hope this is correct and you have a great day :)

5 0
2 years ago
Read 2 more answers
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
Fill in the blank to make the two fractions equivalent.<br><br> /18 = 5/6
Dahasolnce [82]

Answer:

15/18=5/6

hope it helps ;-)

8 0
3 years ago
Read 2 more answers
&lt;1 and &lt;2 form a linear pair. The measure of &lt;2 is six more than twice the measure of &lt;1. Find the measure of &lt;2
MrMuchimi

Answer:

122 Degrees

Step-by-step explanation:

Since we are given that angle 1 and 2 make a linear pair:

angle 1 + angle 2 = 180 degrees ----------------------------(1)

We have also been told that angle 2 is 6 more than twice the measure of angle 1

Which means: angle 2 = (2*angle1)  + 6 -------------------(2)

From putting the value of angle 2 in (1) from (2)

<em>angle 1 + 2*angle 1 + 6 = 180</em>

<em>3*angle 1 = 174</em>

angle 1 = 58 degrees -----------------------(3)

From (1) and (3):

<em>angle 2 + 58 = 180</em>

angle 2  = 122 degrees

Therefore, the measure of angle 2 is 122 degrees

7 0
3 years ago
rewrite f(x)=x^2+8x-20 in the form that would most easily help you identify the zeros of the function
Snowcat [4.5K]

Answer:

f(x) = (x-2) (x+10)

Step-by-step explanation:

f(x)=x^2+8x-20

Factor the right hand side

What 2 numbers multiply to -20 and add to 8

-2 * 10 = -20

-2 + 10 = 8

f(x) = (x-2) (x+10)

Then we can use the zero product property to help us to find the zero's

8 0
3 years ago
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