Hey there
I 've already answered this question twice
by mistake.Kindly check.
F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Answer:
<em>x</em> = 28 Hours
Step-by-step explanation:
if you start with 20 bags done then you take that away from the 1000 and you have 980. Then you do 35x <em>x </em>or 35x28 = 980.
To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
