Answer:
the answer is a
Step-by-step explanation:
i took the test on gogo.net
The answer is 7.
Look at the x=8 and then look up the y-value.
The graph passes (8,7) so therefore when x = 8 the y is 7
Answer:
Step-by-step explanation:
Let x represent the number of years it will take the two colleges to have the same enrollment.
In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is
12900 + 900x
In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is
25000 - 700x
For both colleges to have the same enrollment,
12900 + 900x = 25000 - 700x
900x + 700x = 25000 - 12900
1600x = 12100
x = 12100/1600
x = 7.56
Approximately 8 years
The year would be 2000 + 8 = 2008
Answer:
Let t be the number of toys.
Since, the toy drive already has collected 300 toys
⇒ t+ 300
Also, it is given that the goal of a toy drive is to donate more than 1000 toys.
We get an inequality:
⇒
Solve an inequality:

Subtract 300 from both sides we get

Simplify:
t > 700
Therefore, more than 700 toys does the toy drive need to meet its goal.
An inequality is;
; t > 700
Step-by-step explanation:
12 - 1/2r = ( 13 - 3/2r ) - ( 1 - r )
r - 13/6 = ( 7r - 3/2 ) - ( 2/3 + 6r )
13r + 20 = ( 6r + 7 ) + ( 13 + 7r )
-12 + r = ( -8 - r ) + ( 2r - 4 )