All categories

4 years ago

Why do valid straightedge and compass moves guarantee everyone will produce the same construction?

Mathematics

1 answer:

Klio2033 [76]4 years ago

4 0

Answer:

They do not involve any estimation but to do a specific move.

Step-by-step explanation:

A valid straightedge refers to a drawing tool used for drawing straight lines or for checking the straightness of a line.

A compass, on the other hand, is an instrument often used to measure distance or to draw lines on the radius of a circle.

Therefore, by having a specific measuring or drawing length straightedge and compass moves guarantees everyone will produce the same construction.

You might be interested in

What is the answer to this problem

hichkok12 [17]

C. 7(8) = 56

3(8)(14) = 336

56+336= 392:)

7 0

4 years ago

Read 2 more answers

Abraham has visited 10 countries already. he has a goal of visiting at least 50 countries. he plans to achieve this goal by visi

VikaD [51]

It will take Abraham a total of 8 years to complete his goal.

3 0

3 years ago

If I have the letter x after a number, what does it mean? Ex. 20x = 5

Rzqust [24]

Answer:

It means that 20 times x is 5

also the answer to that problem (20x=5) is 1/4

Step-by-step explanation:

20x means

20 * x

and since 20 * x = 5

divide 5 and 20

5/20 = 1/4

4 0

3 years ago

PLEASE SOMEONE HELP WITH THIS AND EXPLAIN IT!

Nady [450]

Answer: x= 11.15

Step-by-step explanation:

Explanation is in the photo attached

6 0

3 years ago

PLEASE HELP ME!!!

IgorC [24]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

4 0

4 years ago