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Serjik [45]
3 years ago
7

You purchase a television anda blu-ray palter together for $1,759. The blue-ray player, by itself, cost $469. How much did the t

elevision cost?
Mathematics
2 answers:
satela [25.4K]3 years ago
7 0
Both together cost $1759.
That means that sum of the two prices is $1759.
The operation that is the opposite of addition is subtraction.
We subtract $469 from $1759 to find the price of the televition.

$1759 - $469 =

     1759
  -    469
-----------
     1290

$1759 - $469 = $1290

Answer: The price of the television is $1290.


exis [7]3 years ago
6 0
1759 minus 469 equals 1290

The tv costs $1290
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inna [77]

Answer:

C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.

Step-by-step explanation:

The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.

  • There is an n×n matrix C such that CA=I_n.
  • There is an n×n matrix D such that AD=I_n.
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  • A is row-equivalent to the n×n identity matrix I_n.
  • For each column vector b in R^n, the equation Ax=b has a unique solution.
  • The columns of A span R^n.

Therefore the statement:

If there is an n X n matrix D such that AD=​I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:

  • The equation Ax=0 has only the trivial solution x=0.
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The correct option is C.

5 0
4 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Ymorist [56]

It's either choice B. or D. I'm so sorry i cant remember completely.

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Find the dimensions of the rectangle with maximum area that can be inscribed in a circle of radius 10.
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

That will be a square with a diagonal of 20

side length of 20sin45

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prove it you say?

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With a radius of 10, the diagonals of any rectangle inscribed will be 20 units

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A = bh

A = b\sqrt{400 - b^2}

Area will be maximized when the derivative is set to zero

           dA/db = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

                   0 = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

b²/\sqrt{400 - b^2} =  \sqrt{400 - b^2}

                  b² = 400 - b²

                2b² = 400

                  b² = 200

                  b = \sqrt{200}

h = \sqrt{400 - b^2}

h = \sqrt{400 - \sqrt{200}^2 }

h = \sqrt{200}

A = bh

A =  \sqrt{200}•\sqrt{200}

A = 200 units²

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vampirchik [111]

Answer:

5 i believe correct me if im wrong

Step-by-step explanation:

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x<5 ( you answer would then be 5)

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