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ANTONII [103]
3 years ago
7

If you place the north pole of a magnet near the north pole of another magnet, what do you except to happen

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0
They will repel each other
madam [21]3 years ago
8 0
There will be repulsion between the two North poles.
Like poles repel and unlike poles attract.
Hope i helped!
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David worked in the library on Friday and Saturday he worked a total of 7 3/4 hours during these two days if he worked 4 1/4 Hou
aleksandr82 [10.1K]

Answer:

3 1/2 hours.

Step-by-step explanation:

We subtract>

Number of hours worked on a Saturday

= 7 3/4 - 4 1/4

= (7 - 4) + (3/4 - 1/4)

= 3 + 1/2

= 3 1/2 hours.

6 0
3 years ago
Which is more 7/10 or $0.75?
SSSSS [86.1K]

Answer:

I think $0.75

Step-by-step explanation:

$0.75 because 7/10 is 0.7

7 0
3 years ago
Read 2 more answers
Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
Anettt [7]
Splitting up the interval [0, 6] into 6 subintervals means we have

[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]

and the respective midpoints are \dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2. We can write these sequentially as {x_i}^*=\dfrac{2i+1}2 where 0\le i\le5.

So the integral is approximately

\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2

Recall that

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6
\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2
\displaystyle\sum_{i=1}^n1=n

so our sum becomes

\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)
=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2

8 0
3 years ago
Jessica wants to rent a car for 4 days and she's interested in the collision damage waiver nut not the loss damage waiver. if th
Scorpion4ik [409]
The answer should be $238 you multiply the daily cost by 4 and add that to the CDW to get the total cost.
BRAINLIEST
6 0
3 years ago
Read 2 more answers
Factor 5v^2 - 23v - 10​
AfilCa [17]

Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

ac  = -50

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

  • 5v^2 - 23v - 10
  • 5v^2 - 25v + 2v - 10
  • 5v(v - 5) +2(v -5 )
  • (5v + 2)(v - 5)

The factored expression is (5v + 2)(v - 5)

7 0
2 years ago
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