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Alborosie
3 years ago
11

identify a two-digit dividend that will result in a quotient with a remainder of 1 when the divisor is 4.

Mathematics
2 answers:
Kazeer [188]3 years ago
6 0
The answer is 17 because 17 divided by 4 equals 16 with the remainder of 1
Mice21 [21]3 years ago
4 0

Answer:

Number will be of the form a=4q+1

Example: 13,17,21,......

Step-by-step explanation:

We have been given that we have remainder 1, divisor 4

So, we can take many numbers which is 1 greater than the multiple of 4.

the numbers will be of the type:

a=4q+1

We can use Euclidean division algorithm

a=bq+r

Here, b is 4, q we will consider we will consider q>=3

So, let q=3

We will get

a=4(3)+1=13

Put q=4

a=4(4)+1=17

There are many numbers.



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igomit [66]
Answer: 8/45
Just times 2 by 4 and 3 by 15
4 0
3 years ago
Example 15
koban [17]

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8 0
3 years ago
A​ hot-air balloon is 160 ftabove the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) passes dire
Charra [1.4K]

Answer:

73.77 ft/s

Step-by-step explanation:

Let's imagine this situation as a right triangle where the distance between the two points is the hypotenuse.

-Applying Pythagoras theorem:

z^2=x^2+y^2\\\\z=\sqrt{x^2+y^2}\\\\x=dx*t+x_i, x_i=0\\\\y=dy*t+y_i\\\\y_i=160\ ft

#Take the derivative of the first equation and solve for dz:

d(z^2=x^2+y^2)\\\\2z*dz=2x*dx+2y*dy\\\\dz=\frac{x*dx+y*dy}{z}\\\\dz=\frac{x*dx+y*dy}{\sqrt{x^2+y^2}}\\\\\\dz=\frac{dx^2*t+dy(dy*t+160)}{\sqrt{(dx*t)^2+(dy*t)}}

#We then substitute the values given in the question to solve for dz:

dz=\frac{7*66^2+14(14*7+160)}{\sqrt{(66*7)^2+7*14+160}}\\\\=73.78

Hence, the rate of change of the distance between the motorcycle and the balloon 7 seconds ​later is 73.77 ft/s

3 0
3 years ago
I need help answering the question in the picture provided
adoni [48]

answer:

(a).

Equation of circle is <u>x²</u><u> </u><u>+</u><u> </u><u>y²</u><u> </u><u>-</u><u> </u><u>2</u><u>5</u><u> </u><u>=</u><u> </u><u>0</u>

(b).

(-5, 0) » yes

(√7, 1) » no

(-3, √21) » no

(0, 7) » no

Step-by-step explanation:

(a).

If centred at origin, centre is (0, 0)

General equation of circle:

{ \boxed{ \bf{ {x}^{2} +  {y}^{2} + 2gx + 2fy   + c = 0}}}

but g and f are 0:

{x}^{2}  +  {y}^{2}   + c = 0 \\ but :  \\ c =  {g}^{2} +  {f}^{2}  -  {r}^{2}  \\ c =  { - 25}

8 0
3 years ago
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