What is the following quotient? 2-sqrt8/ 4+sqrt12

Mathematics

1 answer:

user100 [1]3 years ago

6 0

Answer:

1-sqrt2/2+sqrt3 or (2-sqrt3-2sqrt2+sqrt6)or (1-sqrt2)(2-sqrt3)

Step-by-step explanation:

2-sqrt8/4+sqrt12

2-2sqrt2/4+2sqrt3

2(1-sqrt2)/2(2+sqrt3)

1-sqrt2/2+sqrt3(Not rationalizing)

(1-sqrt2)(2-sqrt3)/4-3

2-sqrt3-2sqrt2+sqrt6(If you rationalize)

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The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.

These "changes" are indicated with the capital greek letter delta, $\Delta$ , and when you write $\Delta x$ you mean the difference between the finial and the inital values of the variable x:

$\Delta x = x_{\text{fin}} - x_{\text{init}}$

So, the acceleration is defined as

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{v_{\text{fin}} - v_{\text{init}}}{t_{\text{fin}} - t_{\text{init}}}$

In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have

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