Answer:
Formula: pi*r^2
Step-by-step explanation:
The domain of a function is the set of values of x for which a value of y exists. In this case, the only way that a value of y would not exist is for a denominator to equal to zero. If this function is f(x) = 1/(x+1) + 5, then we must find the values of x for which the denominator (x+1) = 0, which is at x = -1.
Therefore the domain is all real numbers except x = -1. In interval notation this can be written as (-infinity, -1), (-1, infinity).
The nearest tenth would be the first decimal place, so the answer would be 23.8
The correct answer to this question is this "domain: x > 1; range: y > 0; Yes, it is a function."
Based from the graph, <span>it has a vertical asymptote at x = 1, so domain is x > 1 </span><span>and since it has horizontal asymptote at y=0, its range is y > 0. So this concludes us to have a domain of x > 1 and a range of y > 0.</span>
Answer:
A reflection over the x-axis
Step-by-step explanation:
