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Scrat [10]
3 years ago
5

A population is estimated to have a standard deviation of 9. We want to estimate the population mean within 2, with a 99% level

of confidence. How large a sample is required? (Round up your answer to the next whole number.)
Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

The sample required is  n = 135

Step-by-step explanation:

From the question we are told that

     The  standard deviation is  \sigma = 9

      The margin of error is E =  2

     

Given that the confidence level is  99%  then the level of  significance is mathematically evaluated as

         \alpha =  100-99

        \alpha =  1 \%

        \alpha =  0.01

Next we will obtain the critical value  \frac{\alpha }{2} from the normal distribution table(reference  math dot armstrong dot edu) , the value is  

             Z_{\frac{\alpha }{2} } =  Z_{\frac{0.05 }{2} } =  2.58

The  sample size is mathematically represented as

          n = [ \frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ]^2

substituting values

           n = [ \frac{ 2.58 *  9 }{2} ]^2

            n = 135

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Answer:

[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

f(x)=\dfrac{1}{x-3}

g(x)=\sqrt{x+5}

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Domain: input values (x-values)

For (f\:o\:g)(x) to be defined:

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Answer:

Step-by-step explanation:

1.

(c+9)^2=64=8^2\\

c+9=±8

either c=8-9=-1

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2.

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