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anygoal [31]
3 years ago
6

To prove that two lines cut by a transversal are parallel, one must show that __________.

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
6 0
I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. To prove that two lines cut by a transversal are parallel, one must show that <span>alternate interior angles are congruent, alternate exterior angles are congruent and corresponding angles are congruent. I hope the answer helped you.</span>
BlackZzzverrR [31]3 years ago
4 0

Answer with explanation:

It is given that two lines are cut by a transversal.To show that ,these two lines are parallel, we must prove

1. Corresponding Angles are equal.

2. Alternate Interior Angles are equal.

3.Sum of angles on the same side of transversal are equal.

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Perpendicular line for 7 x + 5 y equals -1
Leya [2.2K]
7x + 5y = -1 
get: y = mx + c
firstly, subtract 7x from both sides:
5y = -7x -1
divide both sides by 5:
y = (-7x -1)/5:
y= -7x/5 -1/5
therefore the slope, m  = -7/5 in the formula y = mx + c
perpendicular test m1 .m2 = -1
m1 = -7/5, substitute in formula:
(-7/5) x m2 = -1
m2 = -1 /(-7/5) which equals [ invert and multiply] -1 x -5/7 = 5/7
perpendicular slope m2 = 5/7 
new line y=mx +c is:
y = 5/7 x -1/5  

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3 years ago
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Discriminant = sq root of b^2 - 4*a*c =
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The sum of adjacent angles on a straight line would be 180°.

Since x is on a straight line,what we need to do is to deduct the remaining two angles,here's what the equation would be like:

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