Someone help please :)
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The probability is found from a suitable table or probability calculator.
p(z < 1.3) ≈ 0.9031995154
p(z < 1.3) ≈ 0.9031995154
Given that the half life of 3H is 12.3 years.
The amount of substance left of a radioactive substance with half life of
after t years is given by
Therefore, the number of years it will take for 18% of the original tritinum to remain is given by
Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
The amount of substance left of a radioactive substance with half life of
Therefore, the number of years it will take for 18% of the original tritinum to remain is given by
Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>