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kupik [55]
3 years ago
14

A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor of 3

6 N. Find the acceleration of the box in m/s2 Show your work
Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0

The net force is what remains of the pull when we subtract the friction force:

F = 64-36 = 28N

Now, use the law

F=ma

and solve it for the acceleration

a = \dfrac{F}{m}

to get the result:

a = \dfrac{28}{14}=2

zalisa [80]3 years ago
3 0

Answer:

2 m/s²

Step-by-step explanation:

F = applied force in the horizontal direction = 64 N

f = frictional force acting between the box and the floor = 36 N

m = mass of the box = 14 kg

a = acceleration of the box = ?

Force equation along the horizontal direction is given as

F - f = ma

Inserting the values

64 - 36 = 14 a

28 = 14 a

a =  \frac{28}{14}

a = 2 m/s²

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