Question

A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor of 36 N. Find the acceleration of the box in m/s2 Show your work

Answer 1

The net force is what remains of the pull when we subtract the friction force:

$F = 64-36 = 28N$

Now, use the law

$F=ma$

and solve it for the acceleration

$a = \dfrac{F}{m}$

to get the result:

$a = \dfrac{28}{14}=2$

Answer 2

Answer:

2 m/s²

Step-by-step explanation:

F = applied force in the horizontal direction = 64 N

f = frictional force acting between the box and the floor = 36 N

m = mass of the box = 14 kg

a = acceleration of the box = ?

Force equation along the horizontal direction is given as

F - f = ma

Inserting the values

64 - 36 = 14 a

28 = 14 a

a =  $\frac{28}{14}$

a = 2 m/s²