Question

Find the sum of the reciprocals of two consecutive even integers if the larger integer is x. please answer;-;​

Answer 1

Step-by-step explanation:

Let the larger integer be x

Hence, the smaller integer = x-2

Hence,

Reciprocal of the x= 1/x

Reciprocal of x-2= 1/ x-2

Hence. their sum=

$\frac{1}{x} + \frac{1}{x - 2} \\ = \frac{x - 2 + x}{x(x - 2)} \\ = \frac{2x - 2}{ {x}^{2} - 2x}$