Question

Need help with this ​

Answer 1

Let n be the larger integer and n-2 be the smaller integer.

n² - (n - 2)²

= n² - (n - 2)(n - 2)

= n² - (n² - 4n - 4)

= n² - n² + 4n + 4

= 4n + 4

= 4(n + 1)

No matter what value n is, it will always be a multiple of 4.