Given:
The limit problem is:
![\lim_{x\to 3}(x^2+8x-2)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29)
To find:
The limit of the function by using direct substitution.
Solution:
We have,
![\lim_{x\to 3}(x^2+8x-2)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29)
Applying limit, we get
![\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29%3D%283%29%5E2%2B8%283%29-2)
![\lim_{x\to 3}(x^2+8x-2)=9+24-2](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29%3D9%2B24-2)
![\lim_{x\to 3}(x^2+8x-2)=33-2](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29%3D33-2)
![\lim_{x\to 3}(x^2+8x-2)=31](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%203%7D%28x%5E2%2B8x-2%29%3D31)
Therefore, the correct option is D.
Answer:
wow thats a lot let me write this down
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597
Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
n = 133
In short, Your Answer would be 133
Hope this helps!