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lana66690 [7]
3 years ago
15

Determine how much money you will have after 20 years if you invest 20,000$ at 8%, compounded continuously?

Mathematics
2 answers:
Westkost [7]3 years ago
8 0
20 000 * 0.08(8%)= 1600
1600 * 20(years) = 32 000

Therefore you would have $32 000 after 20 years
bazaltina [42]3 years ago
8 0
<span>$32000|</span>Brainiest Please! I need it bad!


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6(y + 7) = 2(y - 3)<br> What is the answer ?
andrew11 [14]

Answer:

Y= -12

Step-by-step explanation:

6(y + 7) = 2(y - 3)

6y+42=2y-6

4y+42=-6

4y=-48

y=-12

7 0
3 years ago
Please help! Will mark brainliest! 20 points!
notsponge [240]

8      3

    -

9      4


Get common denominators.

8(4)      3 (9)

        -

9(4)      4 (9)

=

32      27

      -

36      36

=

5/36

5 0
3 years ago
You will get brainlyest if you do this <br> 16x^0+5x^2*y-1= plz help now
aev [14]

Answer:

=5x^2y+15

Step-by-step explanation:

16x^0+5x^2*y-1=

16x0+5x2y−1

Combine Like Terms:

16+5x2y+−1

=(5x2y)+(16+−1)

=5x^2y+15

Hope this helps!!! If you ever need more help just ask in the comments or somewhere.

7 0
3 years ago
ANYBODY? EASY MATH!
ad-work [718]
Well per dozen they are making 8$ per dozen cupcakes, and 7$ per dozen brownies

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3 years ago
Park rangers tagged fish in a state park to track their population. The function f(x)=200(1.05)x can be used to find the populat
Sedbober [7]

The given exponential function can be used to determine the

population of the fish at different times.

Response:

1. 200

2. 0.05

3. Please find attached the graph of the exponential function and the table

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. Range; [0, ∞)

Domain: [200, ∞)

5. 346 fishes (approximate value)

<h3>How is the population of the fish obtained from the exponential function?</h3>

The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

  • The initial population of the fish is <u>200</u>

2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

  • The growth rate =<u> 0.05</u>

3. Please find attached the graph of the exponential function created

with MS Excel.

The asymptote of the exponential function is the line, <u>y = 0</u>

The table of values is presented as follows;

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. The domain is the possible x-values which is; 0 ≤ x < ∞

The range is the possible y-values which is; 200 ≤ f(x) < ∞

Which gives;

  • Domain; [0, ∞)
  • Range: [200, ∞)

5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹

f(11) = 200 × (1.05)¹¹ ≈ 342

  • The population of the fish after 11 years is <u>346 (fishes)</u>

Learn more about exponential function here:

brainly.com/question/15662160

3 0
3 years ago
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