P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
</span>
<span>P(t) = P(0)[exp(-0.0202t)]</span>
Answer: $59313.58
Step-by-step explanation:
We know that formula we use to find the accumulated amount of the annuity ( ordinary annuity interest is compounded ) is given by :-
, where A is the annuity payment deposit, r is annual interest rate , t is time in years and n is number of periods.
Given : Annuity payment deposit :A= $4500
rate of interest :r= 6%=0.06
No. of periods : m= 1 [∵ its annual]
Time : t= 10 years
Now we get,

∴ the accumulated amount of the annuity= $59313.58
Answer:301.59389
Step-by-step explanation:
254.47+47.12389=301.59389
I'm pretty sure the answer is |x-112|= 4
sorry if its incorrect
Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
Step-by-step explanation:
- We know that when a complex number
is a root of a polynomial with degree 'n' , then the conjugate of the complex number (
) is also a root of the same polynomial.
Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients
Here, 7+5i is a complex number.
So, it conjugate (
) is also a zero of a polynomial function.
Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.