Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct
Step-by-step explanation:
<u />
<u>1.Producción semanal de papas negras</u>:500kg x 12 semanas=6.000kg por 12 semanas de papa negra
<u>2.Producción semanal de batatas:</u> 600 kg x 12 semanas=7.200kg por 12 semanas de batata
<u>3.Producción total</u>: Para obtenerla producción total sumamos el total producido por las 12 semanas entre papa negra y batata.Entonces tenemos:
6.000kg de papa negra + 7.200 kg de batata=<u>13.200 kg </u>de producido total entre papa negra y batata por 12 semanas
1 and 6
16
2,1,and 7
2 and 17
and so on if u get the pattern
Answer:
3
Step-by-step explanation:
8x + 7 = 31 Subtract 7 from both sides
<u> -7 -7</u>
8x = 24 Divide by 8
8x/8 = 24/8
x = 3
8 students know Spanish since 12 students know French and 7 students know Italian
