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motikmotik
3 years ago
7

Your friend asks you to help him study and will pay you 5 dimes the first time you help him. You agree to help if he multiplies

your payment by 5 for each study session. After 2 study sessions, you will receive 25 dimes, and after 3 study sessions, you will receive 125 dimes.
Complete and solve the equation that finds the number of dimes he will pay you after the 7th study session.


= number of dimes for 7th study session

Payment for the 7th study session =
dimes
Mathematics
2 answers:
elena55 [62]3 years ago
8 0

Answer:

Step-by-step explanation:

The answer is 5 exponent ^7

bottom 78,125

the other answers other people answered are totally wrong

zvonat [6]3 years ago
6 0
You would have 78,125 dimes after the 7th study session. 

Which would equal out to $7,812.50
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Five friends are equally sharing 3 packs of football cards.How much of a pack will each friend get?
Mashutka [201]
This answer can be stated in many ways. Each friend will get 3/5, 0.6, or 60% of a pack. (All the answers I previously stated are equal)
4 0
3 years ago
Will name the brainliest
Margaret [11]

Answer:

sin A = 13/85

Step-by-step explanation:

Opposite Angle A is side BC, of length 13.  The length of the hypotenuse is 85.  The sine function is defined as the ratio opp/hyp.  In this problem that ratio is

opp

------ = sin A = 13/85

hyp

We use the inverse sine function arcsin x to determine Angle A:

A = arcsin 13/85 = 8.8 degrees

3 0
3 years ago
Read 2 more answers
Mac has 1/4 hour left of track practice and must be completed 8 laps around the track before he leaves which equation can be use
telo118 [61]

Answer:

(a) Unit = \frac{1}{4}/8

Step-by-step explanation:

Given

Time = \frac{1}{4}

Lap = 8

Required

Determine the time in each lap

The unit time in each lap is calculated by dividing the total time by the number of laps; i.e.;

Unit = \frac{Time}{Lap}

Substitute values for Time and Lap

Unit = \frac{1}{4}/8

5 0
2 years ago
EASY BRAINLIEST PLEASE HELP!!
butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

\displaystyle  \angle DAC =  \angle ACB \\  \ \qquad [\text{ alternate angles theorem}]

2)The lines AB and DC are parallel and BD their transversal therefore,

\displaystyle  \angle BD C=  \angle ABD \\  \ \qquad [\text{ alternate angles theorem}]

3)now in triangle ∆AEB and ∆CED

  • \displaystyle \angle EAD=\angle ECB
  • \angle EDA=\angle EBC
  • \displaystyle AD=BC

therefore,

\displaystyle  \Delta AEB  \cong  \Delta CED

hence,

  • AE=CE
  • DE=BE

Proven

6 0
3 years ago
Multiply and simplify.
miv72 [106K]

Multiply and simplify (3 + i)(4 + 2i)

(3 + i)(4 + 2i) = (3*4) + (3*2i) + (4*i) + (2i*i) = 12 + 6i + 4i + 2i^2

i^2 = -1

12 + 6i + 4i + 2i^2 = 12 + 6i + 4i -2 = 10 + 10i

Use the imaginary number i to rewrite the expression:

--\sqrt{-16} \\(-1)\sqrt{(-1)16}\\(-1)\sqrt{16}i\\(-1)4i\\-4i

8 0
3 years ago
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