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2 years ago

15

Please help I will mark brainly . Need done now !

1 answer:

Dmitry [639]2 years ago

4 0

To change a probability, p, to odds, do p/(1 - p)

Each line on the left column is 1 through 5.
Each line on the right column is A through E.

1C
2E
3A
4D
5B

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If 2^3^x/8^y = 1/16, what is the value of x - y?

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2 years ago

The graph of is shown below. What is the value of y when x = 0?

jarptica [38.1K]

$\huge\text{Hey there!}$

$\huge\textsf{This equation/question should be easy to}\\\\\huge\textsf{to solve for because, we have everything you}\\\\\huge\textsf{you will need on your graph and somewhat in}\\\\\huge\textsf{the question because it already gave you the}\\\\\huge\boxed{\mathsf{x-intercept}}\huge\textsf{.}$
$\mathsf{y = |x| - 2}$

$\mathsf{y = |0| - 2}$

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1 year ago

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Sydney is going to a carnival that has games and rides. Each game costs $1.25 and each ride costs $2.25. Sydney spent $24.25 alt

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2 years ago

A,B and C are the vertices of one triangle.

dsp73

Answer:

Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is $\frac{AD}{DB}=\frac{AE}{EC}$ , then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates= $(\frac{4+2}{2},\frac{6-2}{2})=(3,2)$ and Mid Point E has coordinates= $(\frac{4-2}{2},\frac{6-4}{2})=(1,1)$

Now, AD= $\sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}$

DB= $\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}$

AE= $\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}$

EC= $\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}$

Now, $\frac{AD}{DB}=\frac{AE}{EC}$

= $\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}$

Hence, $\frac{AD}{DB}=\frac{AE}{EC}$

Thus, By basic proportionality theorem, DE is parallel to BC.

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3 years ago

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