All categories

2 years ago

Please help I will mark brainly . Need done now !

Mathematics

1 answer:

Dmitry [639]2 years ago

4 0

To change a probability, p, to odds, do p/(1 - p)

Each line on the left column is 1 through 5.
Each line on the right column is A through E.

1C
2E
3A
4D
5B

You might be interested in

My estimate was 2,808 is that a reasonable estimate and why

vova2212 [387]

<span>My estimate was 2,808 is that a reasonable estimate and why

312*9

9*2=18>>9*10=90>>9*300=2700

2700+18+90=>>2,808</span>

5 0

3 years ago

Which of the following ordered pairs is a solution to the equation? (-4,-1) (-2,0) (0,3) (9,1)

Natalija [7]

The answer is (0,3) the line hits at positive 3

3 0

2 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

1 year ago

Explain how you can use place value patterns to describe how 50 and 5000 compare

salantis [7]

The place value pattern is a system of patterns of tens in which every place value is ten times the value on its right. The place value pattern system is used to <span>write numbers that are 10 times as much as or 1/10 of any given number.
The place values in the pattern are: ones, tens (10*ones), hundreds (10*tens), thousands (10*hundreds),...
So, 50 = 5 tens
5000= 5 thousands, 0 hundreds, 0 tens, 0 ones

So, 5000 > 50</span>

3 0

3 years ago

Which of the following equations matches the graph above?

Ierofanga [76]

Yes , I agree w them I’m gonna go with the answer D.

3 0

2 years ago