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4 years ago

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ula1" title=" \frac{x(x+1)^2(x-5)}{x(x+2)(x-5)^3} " alt=" \frac{x(x+1)^2(x-5)}{x(x+2)(x-5)^3} " align="absmiddle" class="latex-formula"> in simplest forms. Show your work.

1 answer:

Marizza181 [45]4 years ago

5 0

$\bf \cfrac{x(x+1)^2(x-5)}{x(x+2)(x-5)^3}\implies \cfrac{(x+1)^2}{(x+2)(x-5)^2}$

all we can really cancel is one of the (x-5) and the "x", is all.

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3 years ago

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3 years ago

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3 years ago

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Answer:

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<em>Whenever we have a dilation with a scale factor b, we get the new point as:</em>

<em>Let original point be (x,y), then the dilation would make it (bx, by).</em>

<em />

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Now let vertex B have coordinates (x,y). <u>Midpoint of BD:</u>

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<em />

<em>and</em>

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<em>recalling dilation of scale factor 2 rule we said at the beginning, B' would be twice of each coordinate. Hence B' = (16,14)</em>

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3 years ago