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lawyer [7]
3 years ago
5

When Ava went to bed, the temperature was 3°F. When she woke up, the temperature had decreased by 6°F.

Mathematics
2 answers:
AnnZ [28]3 years ago
5 0

Answer:

-3°F

Step-by-step explanation:

3-3=0, -3 more is -3

Ede4ka [16]3 years ago
4 0
Ava woke up to be -3 Fahrenheit
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Help help help help
ale4655 [162]

t = 2/3. Multiply the numbers in the parentheses by -1. It becomes 9t + -3t + -3 = 1. Combine like terms to get 6t + -3 = 1. Add 3 to both sides to get 6t = 4. Divide both sides by 6. t = 2/3

3 0
3 years ago
Alex got 9 hits in his first 22 at bats. If his hitting rate remains constant, how many at bats would he have to have to reach 5
nikklg [1K]

Answer:

122.2222 repeating

Step-by-step explanation:

3 0
3 years ago
If angle ABC is one degree less than three times angle ABD and angle DBC=47 find each measure
Contact [7]

It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.

Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC

⇒ Angle ABC = Angle ABD + Angle DBC

Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree

Let angle ABD be x

⇒ Angle ABC = 3x-1

Also, Angle ABC = Angle ABD + Angle DBC

Substituting the values in the above equations

⇒ 3x-1 = x+47

⇒ 2x = 48

⇒ x = 24

So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree

8 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Find the difference:7 7/8-3 1/4=?
Arlecino [84]

Answer:

4 5/8

Step-by-step explanation:

7 7/8 - 3 1/4

7 7/8 - 3 2/8

4 5/8

8 0
3 years ago
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