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Mamont248 [21]
3 years ago
8

100 points please help asap I will also give brainiest! 100 points please HELP asap!!! (05.01)Which statement best describes the

area of the triangle shown below?
It is one-half the area of a rectangle of length 4 units and width 2 units.
It is one-half the area of a square of side length 4 units.
It is twice the area of a rectangle of length 4 units and width 2 units.
It is twice the area of a square of side length 4 units.

Mathematics
2 answers:
Readme [11.4K]3 years ago
6 0

It is one-half the area of a rectangle of length 2 units and width 4 units.

Step-by-step explanation:

Anna [14]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

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Find the distance between the points (1,8) and (9, 2).
grin007 [14]

Answer:

distance = \sqrt{(x_{1} -x_{2})^2+(y_{1} -y_{2})^2  }\\\\

             =\sqrt{(9-1)^2+(2-8)^2  }\\\\=\sqrt{8^2 + 6^2}\\\\=\sqrt{64 +36 }\\\\=\sqrt{100} = 10units

6 0
3 years ago
A woman wishes to rent a house within 9 miles of her work. If she lives x miles from her work, her transportation cost will be c
I am Lyosha [343]

Answer:

the woman has to live 1 mile from work to minimize the expenses

Step-by-step explanation:

Given the data in the question;

the distance within 9 miles ⇒ 0 < x > 9

Total costs Q = cx + 4c/( x + 1)

costs should be minimum  ⇒ dQ/dx = 0

⇒ d/dx [ cx + 4c/( x + 1) ] = 0

⇒ ( x + 1)² = 4

take square root of both side

√[ ( x + 1)² ] = √4

x + 1 = 2

x = 2 - 1

x = 1

Therefore, the woman has to live 1 mile from work to minimize the expenses

5 0
3 years ago
1. Suppose y varies directly as x. If y = 3 when x = 15. then find x when y = 5.
KATRIN_1 [288]

Answer:

when y=3,X=15

here X is five times the value of y

so now when y= 5 then the value of X will be 25

hope you understand......

8 0
3 years ago
How do you express three less than a number
Lynna [10]

Answer:

x - 3

Step-by-step explanation:

let's call the unknown number x to express its value that's three less than actual number we say x - 3

5 0
3 years ago
What are the zeros in the function
Schach [20]
f(x)=x^3+x^2-6x\\\\text{The zeros:}\\\\f(x)=0\to x^3+x^2-6x=0\\\\x(x^2+x-6)=0\\\\x(x^2+3x-2x-6)=0\\\\x[x(x+3)-2(x+3)]=0\\\\x(x+3)(x-2)=0\iff x=0\ \vee\ x+3=0\ \vee\ x-2=0\\\\x=0\ \vee\ x=-3\ \vee\ x=2

Answer: -3; 0 and 2

6 0
4 years ago
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