What is the VOLUME of the RIGHT RECTANGULAR PRISM? DO NOT ENTER UNITS!

Identify three ways that ocean plants cycle carbon

pav-90 [236]

Carbon dioxide from the atmosphere dissolves in the surface waters of the ocean. Some of the carbon dioxide stays as dissolved gas, but much of it gets turned into other things. Photosynthesis by tiny marine plants (phytoplankton) in the sunlit surface waters turns the carbon into organic matter.

8 0

3 years ago

What is log base 7 of 252

rjkz [21]

Answer:

2.84

Step-by-step explanation:

Recognize that 252 = 7*36

and so:

log base 7 of 252 = log base 7 of 36 + log base 7 of 7, or

log base 7 of 36 + 1

So the most you can simplify log base 7 of 252 is to write 1 + log base 7 of 36.

Or, if you want to use the change of base formula, you could do the following:

log 36

log base 7 of 36 = -------------- = 1.84

log 7

and so log base 7 of 252 would come out to

1 + log base 7 of 36 = 1 + 1.84 = 2.84

Check: does 7^2.84 = 252? YES. So we know that:

1 + log base 7 of 36 = 2.84

4 0

3 years ago

1) Write an equation in slope-intercept form of the line with slope of 6 and y-intercept of -3. Then graph the line. 2) Write an

asambeis [7]

Answer:

An equation in the slope-intercept form is:

y = a*x + b

Where a is the slope, and b is the y-intercept.

a)

Here we have a slope of 6 and a y-intercept of -3

Then the equation is:

y = 6*x - 3

Now we want to graph this.

To graph it, we first need to find two points (x, y) that belong to this equation, then we can graph the points, and connect them with a line.

To find the points, we evaluate in two different values of x.

x = 0

y = 6*0 - 3 = -3

Then we have the point (0, -3)

x = 1

y = 6*1 - 3 = 3

Then we have the point (1, 3)

The graph of this line can be seen in the image below (the red one)

b) Similar to before, here the slope is -3/5, then the equation is something like:

y = (-3/5)*x + b

Now we also know that the line passes through the point (-10, 8)

This means that when x = -10, we must have y = 8

Replacing these two in the equation we get:

8 = (-3/5)*-10 + b

8 = 6 + b

8 - 6 = 2 = b

Then this equation is:

y = (-3/5)*X + 2

The graph can be found in the same way as before, the graph of this function can also be seen in the image below (the green one)

6 0

2 years ago

If the ratio is 50g to 300 ml how many ml would be needed for 83g

Natali [406]

Answer:

498 ml would be needed for 83g.

Step-by-step explanation:

♧We can solve using proportion.

$\frac{50 \: g}{300 \: ml} = \frac{83 \: g}{x} \\ \\ \frac{24900}{50} = \frac{50x}{50} \\ \\ 498 = x$

▪Happy To Help <3

4 0

2 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

Hence, circle Q has a smaller radius

4 0

3 years ago