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VLD [36.1K]
3 years ago
11

PLEASE HELP! I will give brainliest! If an object is dropped from a tall building, then the distance (in feet) it has fallen aft

er t seconds is given by the function d(t)=16t^2.
Determine the average speed (rate of change) between 3 and 8 seconds.
Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

160ms^{-1}

Step-by-step explanation:

d(t)=16t^2\\

To work out rate of change of a function, you must differentiate it.

\frac{\Delta d(t)}{\Delta t} =32t

d'(8)-d'(3)=32*8 - 32*3=32*5=160ms^{-1}

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Helppppp! what is 2+6????
yaroslaw [1]

Answer:

8...I want these points lol

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
You start driving north for 16 miles, turn right, and drive east for another 30 miles. At the end of driving, what is your strai
Maru [420]

The distance between starting and ending point is 34 miles.

Step-by-step explanation:

Given,

Car moves 16 miles to north then 30 mile to east.

It forms a right angle triangle.

The straight line distance from starting to ending point represents hypotenuse.

To find the distance between starting and ending point.

Formula

By <em>Pythagoras theorem,</em>

h² = b²+l² where h is the hypotenuse, b is base and l is the another side.

Taking, b=16 and l=30 we get,

h² = 16²+30²

or, h = \sqrt{256+900}

or, h = \sqrt{1156} = 34

Hence,

The distance between starting and ending point is 34 miles.

5 0
3 years ago
What is the solution set of {x|x&lt;-3} intersection {x|x&gt;5}?
ziro4ka [17]
There’s no solution because x is less than 3 there is no way is greater than 5.

Hope this helps!
8 0
3 years ago
Marine biologists have been studying the effects of acidification of the oceans on weights of male baluga whales in the Arctic O
PSYCHO15rus [73]

Answer:

c. 61.25 kg

Step-by-step explanation:

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.

a. 15.31 kg

b. 51.40 kg

c. 61.25 kg

d. 80.49 kg

Margin of Error Formula= z × Standard deviation/√n

95% confidence interval = 1.96

Standard deviation = 125kg

n = 16 samples

Margin of error= 1.96 × 125/√16

= 1.96 × 125/4

= 245/4

= 61.25kg

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg

6 0
3 years ago
WILL GIVE BRAINLIEST FOR CORRECT ANSWER !
lesya692 [45]

Answer:

neither

Step-by-step explanation:

The second and 3rd one can be modeled by by y = 100/x but the first one and the fourth one do not follow that, so the answer is neither. The first and fourth are y = 80/x

Put the values in and you will see the equations for yourself.

One

y = 80/2

y = 40

The 80 came from looking at this as an indirect variation. y = k/x

y = 40

x = 2

y = k/x

40 = k/2  Multiply both sides by 2

40 * 2 = k

k = 80

Two

y = k/x

20 = k/5

k = 20 * 5

k = 100

8 0
3 years ago
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