Question

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Hi! Can anyone please help me with my homework? I would be grateful. No spam.

Thanks in advance.

$\bold{(4t-3)^{5}}$

Answer 1

Answer:

${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

Step-by-step explanation:

Question:-

• To find the Binomial theorem form of $\bold{(4t-3)^{5}}$

As we know:-

As in Binomial theorem :-

• ${(x - y)}^{5} = {x}^{5} - 5 {x}^{4} y + 10 {x}^{3} {y}^{2} - 10 {x}^{2} {y}^{3} + 5x {y}^{4} - {y}^{5}$

Solution :-

$= {(4t - 3)}^{5}$

• Hence, on using the Binomial theorem,

$= {(4t)}^{5} - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3} {(3)}^{2} - 10 {(4t)}^{2} {(3)}^{3} + 5(4t) {(3)}^{4} - {(3)}^{5}$

• On formatting

$= {1024t}^{5} - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2} )(27) + 5(4t) (81) - 243$

• On further formatting.

$= {1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

Hence, the required answer is :-

${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$