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2 years ago

10

Find the equation line

1 answer:

DanielleElmas [232]2 years ago

4 0

Answer:

sorry I don't know

Step-by-step explanation:

hdkajdbdbsjjsvdchksbevd

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Jace invested $380 in an account paying an interest rate of 6.2% compounded continuously. Assuming no deposits or withdrawals ar

SOVA2 [1]

Answer: 960

Step-by-step explanation:

5 0

2 years ago

the 22 students bought a Valentine's presents they purchased 2 dozen for 22.95$ per and a box of chocolates for 13.45$ they spli

irina [24]

Answer:

I think the answer is b

Step-by-step explanation:

I think its b because, $22.95 plus $13.45 equals $36.40. And divide that by 22, and get $1.60 rounded is $2.00. I hope this can help.

3 0

2 years ago

Y+1=-2x-3 in standard form

nignag [31]

Hope this answer is helpful for you

7 0

2 years ago

Whats the roots of the following three problems:

klemol [59]

QUESTION 1

The given function is

$f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}$

We simplify to get;

$f(x)=\frac{x-3}{x+2}$

This function is equal to zero when $x-3=0$

$\Rightarrow x=3$

QUESTION 2

The given function is

$f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}$

$f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}$

We factor to get;

$f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}$

$f(x)=\frac{5(x-1)}{(2x-3)}$

This function equals zero when

$5(x-1)=0$

$x=1$

QUESTION 3

The given function is

$f(x)=\frac{x^3-8}{x^2-6x+8}$

We factor to get,

$f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}$

$f(x)=\frac{x^2+2x+4}{x+4}$

The function equals zero when $x^2+2x+4=0$

$D=b^2-4ac$

$D=2^2-4(1)(4)$

$D=-12$

Hence the equation has no real roots.

The complex roots are

$x=-\sqrt{3}i-1$ or $x=-1+\sqrt{3}i$

4 0

2 years ago

Index notation of 5 x 5 x 5 x 5

anygoal [31]

5^4 (five to the 4th power)

6 0

2 years ago

Read 2 more answers