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3 years ago

The expression on the left side of an equation is shown below.

Mathematics

2 answers:

cluponka [151]3 years ago

7 0

Answer:

4) x

Step-by-step explanation:

The expression on the left side simplifies to:

-4(x - 2) + 5x =

= -4x + 8 + 5x

= x + 8

To have an equation with no solution, you need the same x term on the right side but a different constant term. The x term on the left side is x. You need x on the right side but with a constant term different than 8.

Answer: 4) x

nlexa [21]3 years ago

6 0

Expression that can be written in the box on the other side of the equation will be x

Step-by-step explanation:

The left side of equation is: $-4(x-2)+5x$

Simplifying the equation we get:

$-4(x-2)+5x\\=-4x+8+5x\\=-4x+5x+8\\=x+8$

An equation has no solution when, we cannot find the value of x.

So, The order side of equation can be x

i.e,

$-4(x-2)+5x=x\\x+8=x\\x-x=-8\\0\neq 8$

So, expression that can be written in the box on the other side of the equation will be x

Keywords: Solving Equations

Learn more about solving equations at:

#learnwithBrainly

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Answer:

x = - 10

Step-by-step explanation:

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x = - 10

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Identify and interpret (explain) one other point on the graph.?

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Answer:

can i getttt a pictture

Step-by-step explanation:

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3 years ago

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Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

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3 years ago

Please solve in the picture!

iris [78.8K]

Answer:

Step-by-step explanation:

As we know that from a theorem,

A greater angle of a triangle is opposite a greater side. Let ABC be a triangle in which angle ABC is greater than angle BCA; then side AC is also greater than side AB. For if it is not greater, then AC is either equal to AB or less.

As we have angle A =120 so it means the other 2 angles will be less than angle A , hence the opposite side to angle A is BC ,

Hence BC line is the longest line in triangle ABC

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2 years ago

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