All categories

3 years ago

10 points to the person who answers this whole thing and I will mark you as brainliest.

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Perimeter is found by adding together all the lengths of the sides. For us, that is x + (2x + 5) + (6x - 17) + (3x + 2). Now we will just combine like terms. We can also drop the parenthesis because they do nothing for us and mean nothing to the problem.

x + 2x + 5 + 6x - 17 + 3x + 2 becomes

12x - 10

You might be interested in

Write a story or situation that can be represented by the given equation.<br><br> 4a+5=12a−11

Leto [7]

Answer:

a = 4

Step-by-step explanation:

STEP 1) 4a - 16 = 4 • (a - 4)

3 0

3 years ago

Read 2 more answers

Ariel takes 3 pages of notes during each hour of class. In all, how many hours will Ariel

7nadin3 [17]

Answer:

12 hours

Step-by-step explanation:

36 divide that by 12 and she has 12 hours to write on 36 pages

7 0

3 years ago

Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal

Elina [12.6K]

Answer:

The correct answer would be 2:1

Step-by-step explanation:

In order to find this, start with the ratio as it is written and sub in the values. Then simplify to the lowest possible terms.

Ran:Walker

8:4

2:1

6 0

3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$