Answer:
at least 5
Step-by-step explanation:
<u><em>If the question was similar to the one given below </em></u>
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?
<em><u>The answer would be as follows</u></em>
If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
4C2= 6 ways to use these letters and the comma
If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
5C2= 10 ways to use these letters and the comma
If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
6C2= 15 ways to use these letters and the comma
We need the least number of the alphabets to assign codes to 12 participants.
So the least number of alphabets is 5 because it can give codes to at least to 12 people .
Pair of alphabets + distinct letter ≥ 12
5 + 1 ≥ 12
6c2 ≥ 12
15 ≥ 12
Answer:
Step-by-step explanation:
p = (3n + a)/(n + a)
Cross multiply
p(n + a) = 3n +a
pn + pa = 3n + a
pa - a = 3n - pn
a(p - 1) = n(3 - p)
Dividing by p - 1
a = n(3 - p)/(p - 1)
Answer:
f(x)=x(x- a) (x - b) 2 that is the answer good luck
Answer: Y= 1.6
Step-by-step explanation: 1.6 + 0.4 =2
Well first I think you need to divided <span />
