The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:
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How to write the polynomial?</h3>
A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:
Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.
Then this polynomial is equal to:
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Answer:
x = 5, y = 2
Step-by-step explanation:
just trust me, I used a calculator
Answer:
70
Step-by-step explanation:
The angle not marked in the top triangle is 40 degrees since it is an isosceles triangle. That makes the angle opposite it in the other triangle 40 degrees since they are vertical angles and vertical angles are equal.
The bottom triangle has 3 angles that sum to 180 degrees, The other angle not marked is also y since it is an isosceles triangle.
40 + y +y = 180
Subtract 40 from each side and combine like terms
40-40 +2y = 180-40
2y = 140
Divide by 2
2y/2 = 140/2
y = 70
Answer:
Step-by-step explanation:
A rectangle is shown with length x plus 10 and width 2 x plus 5.
so the rectangle area = length * width
= (x + 10) * (2x + 5)
an unshaded square with length x plus 1 and width x plus 1
so the unshaded square area = (x + 1) * (x + 1)
the shaded area = rectangle area - square area
= (x + 10) * (2x + 5) - (x + 1) * (x + 1)
= (2x^2 + 20x + 5x + 50) - (x^2 + x + x + 1)
= x^2 + 23x + 49
