Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Answer:

Step-by-step explanation:
The equation of a quadratic function in vertex form is given by:

Where (h,k) is the vertex.
It was given in the question that the vertex of the parabola is (-1,4).
When we substitute the vertex into the formula we get:

The parabola also passes through (4,19) hence it must satisfy its equation.



We divide both sides by 25 to get:

Hence the quadratic function is:

The answer is choice D because if you combine the like terms, you get 15-23i
i hope that helps!!!!
Answer:
$6960
Step-by-step explanation:
p is not the principle. It is the principal.
I = prt
p = $6000
r = 8% = 0.08
t = 2
I = ($6000)(0.08)(2)
I = $960
Total amount after 2 years = principal + interest
Total amount = $6000 + $960
Total amount = $6960