Put the first equation in slope-intercept form, or y = mx + b. Start by subtracting y from both sides.
2x - y = -10, subtract 2x from both sides.
-y = -10 - 2x
Divide both sides by negative one.
y = 10 + 2x
To find the slope when the equations are in slope-intercept form you look at the coefficient of x. The first equation has the slope of 2 (which we just found), and the second equation has the slope of -2.
Parallel lines have the same slope and perpendicular lines have opposite reciprocal slopes. Since 2 and -2 are neither of these, your answer is neither.
We are seeing 30, 60, 90, triangles, and 45, 45, 90, triangles.
13. 3 root 3
14. 5 root 2
15. 7/2 root 2
16. 3/2 root 2
17. 7.5 root 3
19. bc is squared root 37
20. 32 + 32 root 3
Answer:
Yes Jeff is the correct answer
Step-by-step explanation:
Answer:
No it is still 11 feet from the water at 2 seconds
2.1651 seconds is when it will hit the water
Step-by-step explanation:
h(t) = -16 t^2 +75
This is the formula for the distance
The -16t^2 is due to gravity and the 75 is the height above the bridge
We want to know the height a t =2
h(2) = -16 (2)^2 +75
h(2) =-64 +75
h(2) = 11
The rock will be 11 ft above the water
When will the rock hit the water
h = 0
0 = -16 t^2 +75
Subtract 75 from each side
-75 = -16t^2 +75-75
-75 = -16t^2
Divide by -16
-75/-16 = -16t^2 /-16
75/16 = t^2
Take the square root of each side. We only take the positive square root since time must be positive
sqrt(75/16) =t
5/4 sqrt(3) = t
2.1651 seconds = t
