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Salsk061 [2.6K]
3 years ago
10

Two entertainment venues are planning to expand the size of their audiences and each has decided on the rate at which it can inc

rease its audience size. The functions below represent the prospective audience sizes of the venues after t years.
City Arts Center : C(t) = 250(1.45)^t/5
Oakwood Auditorium : C(t) = 200(1.55)^t/7

Which statement is true about the audience size of the venues?

The annual rate of increase in the audience size of Oakwood Auditorium is greater than the annual rate of increase in the audience size of City Arts Center.

The annual rate of increase in the audience size of Oakwood Auditorium is less than the annual rate of increase in the audience size of City Arts Center.

The annual rate of increase in the audience size of Oakwood Auditorium is the same as the annual rate of increase in the audience size of City Arts Center.

The annual percentage rates of increase in the audience sizes cannot be determined from this information.
Mathematics
2 answers:
NNADVOKAT [17]3 years ago
4 0
Let us see... ideally we would like to have all equations with the same exponent or the same base so that we can compare the rates. Since the unknown is in the exponent, we have to work with them. In general, x^(y/z)= \sqrt[z]{x^y}.
Applying this to the exponential parts of the functions, we have that the first equation is equal to:
250*(\sqrt[5]{1.45} ^t)=250*(1.077)^t
The second equation is equal to: 200* (1.064)^t in a similar way.
We have that the base of the first equation is higher, thus the rate of growth is faster in the first case; Choice B is correct.

ololo11 [35]3 years ago
4 0

Answer: The annual rate of increase in the audience size of Oakwood Auditorium is less than the annual rate of increase in the audience size of City Arts Center.

Step-by-step explanation:

Here, the function that shows the audience sizes of the venues after t years. by City Arts Center is,

C(t) = 250(1.45)^{\frac{t}{5}}

⇒ C(t) = 250((1.45)^{\frac{1}{5}})^t\implies =250(1.07714358779)^t

Thus, the increasing rate of the function is 0.07714358779.

Similarly, the function that shows the audience sizes of the venues after t years. by Oakwood Auditorium is,

C(t) = 200((1.55)^\frac{1}{7})^t\implies C(t) = 200(1.06460926794)^t

Thus, the increasing rate of the function is 0.06460926794.

Since, 0.07714358779 > 0.06460926794

Hence, The annual rate of increase in the audience size of Oakwood Auditorium is less than the annual rate of increase in the audience size of City Arts Center.

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When x = 4, y = 1<br> x^2 + 3xy – 7y^2
densk [106]

Answer:

21

Step-by-step explanation:

i worked out the problem

4 0
3 years ago
What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
Arte-miy333 [17]

Answer:

The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}.

Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

6 0
4 years ago
Kelvin rolls a dice twice. The first number he gets is 4. The sum of the two numbers is smaller than 8. Which number CANNOT be t
VLD [36.1K]

Answer:

5, 6

Step-by-step explanation:

When Kelvin rolls the dice twice, he can't get more than a 4 because if he did, the sum of the two numbers would be more than a 8. So, the numbers that cannot be the second number is 5 and 6.

5 0
3 years ago
2 Divided by 1 / 5. Rlly need help on this
Natasha_Volkova [10]

Answer:

The answer will be 10

Step-by-step explanation:

2/1/5=10

3 0
3 years ago
Please show the work you did when getting your answer please! Thank you.
N76 [4]
4x + 18 = 10x
Subtract 4x from both sides
18 = 6x
Divide by the coefficient to get X by itself.
3 = x
Each of the square's sides = 3.
4 0
4 years ago
Read 2 more answers
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