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3 years ago

Evaluate -32 + (2-6)(10).

Mathematics

2 answers:

vitfil [10]3 years ago

3 0

Answer:

-72

Step-by-step explanation:

-32 + (2-6)(10)

PEMDAS

Parenthases first

(-4)(10)

multiply together

(-40)

Then just add the -32 and since a negative plus a negative is always negative the answer is going to be negative

-32 + (-40)

= -72

hodyreva [135]3 years ago

3 0

Answer:

-49

Step-by-step explanation:

hope it helped :)

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A fashion designer makes and sells hats. The material for each hat cost $5.50. The Hats sell for $12.50 each. The designer spend

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The designer must sell 200 hats for breaking even.

Step-by-step explanation:

Given,

Cost for material for each hat = $5.50

Selling price of each hat = $12.50

Cost spend on advertising = $1400

Let,

x represents the number of hats.

Revenue = 12.50x

Costs = 5.50x+1400

For breaking even,

Revenue = Cost

$12.50x=5.50x+1400\\12.50x-5.50x=1400\\7x=1400$

Dividing both sides by 7

$\frac{7x}{7}=\frac{1400}{7}\\x=200$

The designer must sell 200 hats for breaking even.

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2 years ago

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cricket20 [7]

In an isosceles triangle, two sides are equal to each other. So, we know that the third side is either 6 or 15 inches.

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Reil [10]

Given

$x+1 = \sqrt{7x+15}$

We have to set the restraint

$x+1\geq 0 \iff x \geq -1$

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

$(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0$

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

$x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}$

So, we have to impose

$x-7\geq 0 \iff x \geq 7$

Squaring both sides, we have

$(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0$

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

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