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3 years ago

If f(x) and g(x) are quadratic functions but (f + g)(x) produces the graph below, which statement must be true?

Mathematics

1 answer:

aksik [14]3 years ago

4 0

Answer:

The leading coefficients of f(x) and g(x) are opposites.

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En el experimento Extraer una carta de una baraja española se consideran estos sucesos: A= 《Salir as 》 B= 《salir bastos 》 Calcul

Ganezh [65]

Answer:

They are compatible

Step-by-step explanation:

The first thing is to say that an "ace" and that it is a "coarse"

"ace" is card number 1. Group A

"coarse" is a type of the deck, found from number 1 to card 13. Group B

Thus:

Calculate A U B:

1 to 13 + 1 of the other types of cards in the deck.

At intersection B:

1 of "coarse"

Therefore, if group A is compatible with group B

7 0

3 years ago

PLEASE HELP ME SOLVE THIS WILL GIVE U BRAINIEST!!!!!!!!!!

blsea [12.9K]

Answer: 6.93

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given f(x) = x^2 − 2x − 5.

lukranit [14]

Answer:

$(x - 1)^2 - 6$

Step-by-step explanation:

You need to know:

Vertex form = $a(x -h)^2 + k$

The vertex is at

(h, k)

Need to know about perfect squares

Need to know how to complete the square.

-----------------------------------------------------------------------------------------

To convert $x^2-2x-5$ you need to complete the square on the equation.

Complete the Square $x^2 - 2x -5$

$x^2 - 2x -5$

$(x^2 - 2x) -5$

Divide -2 by 2 and then square it.

$\frac{-2}{2} = -1$

$-1^2 = 1$

Add the one to the parentheses and subtract the one from the 5

$(x^2 - 2x +1) -5 -1$

Square $(x^2 - 2x +1)$

$(x-1)^2$

Now we have

$(x - 1)^2 -5 -1$

Next add -5 - 1 = -6

$(x - 1)^2 - 6$

Our quadratic is in vertex form now.

Vertex form = $a(x -h)^2 + k$

our equation = $(x - 1)^2 - 6$

Vertex = (1, -6)

5 0

4 years ago

A car travels at an average speed of 50 km/h for 1.5 hours. How far did the car travel in km?

boyakko [2]

Answer:

75 km

Step-by-step explanation:

(50km/h)(1.5h) = 75km

7 0

2 years ago

Find the minimum value of

viva [34]

Answer:

Find the minimum and maximum values of the objective function subject to the given constrants. Objective function: C= 2x + 3y

Constraints:

x>0

y>0

Comment: These two conditions tell you the answers are in the 1st Quadrant.

-----------------------------

x +y < 9

Graph the boundary line: y = -x+9

Solutions points are below the boundary line and in the 1st Quadrant.

8 0

3 years ago