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mojhsa [17]
2 years ago
12

What is 3 47/99 in decimal form?

Mathematics
2 answers:
ddd [48]2 years ago
5 0
The answer is 3.<span>474747474747475</span>
LiRa [457]2 years ago
3 0
The answer is 3.47 repeating
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Someone help me please
Mazyrski [523]

Answer:

x = -7

Step-by-step explanation:

The whole line is 12

the whole line is also   x + 14  and  x + 12

  so make them equal:

      x+14     +      x +12     = 12  

       2x   + 26   = 12        now subtract 26 from both sides

               2x = - 14           now divide both sides by 2

                 x = -7

5 0
1 year ago
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A​ 12-sided die is rolled. The set of equally likely outcomes is​ {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling
UNO [17]
1/6 is the probability of rolling a dice and getting less than 3.
7 0
2 years ago
Without drawing the graphs, find the points of intersection of the lines: a 7x+4y=23 and 8x–10y=19
emmainna [20.7K]

Answer:

(3,0.5)

Step-by-step explanation:

The given system has equations:

7x + 4y = 23 \\ 8x - 10y = 19

Let us multiply the second equation by 4 and the first equation by 10.

70x + 40y = 230 \\ 32x - 40y = 76

We add both new equations to get:

102x = 306 \\ x =  \frac{306}{102}  = 3

Put x=3 into the first equation and solve for y.

7(3) + 4y = 23 \\ 21 + 4y = 23 \\ 4y = 23 - 21 \\ 4y = 2 \\  y =  \frac{1}{2}

The point of intersection is the solution to the system of equation which is (3,0.5)

8 0
3 years ago
I forgot someone help me plz
o-na [289]
Write the conjugates of them then FOIL both the top and bottom, then factor

5 0
2 years ago
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The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
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