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3 years ago

14

Dawson rakes leaves in his neighborhood. The equation y = 10x represents the amount of money he earns. What is the constant of p

roportionality? A. 1 C. 10 B. 5 D. 20

1 answer:

Valentin [98]3 years ago

3 0

The constant of proportionality is equal to k in y=kx. In y=10x, the k value is 10.

Final answer: C. 10

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Klio2033 [76]

The human ran 0.45 miles per minute.

27 divided by 60 = 0.45

The 60 is the number of seconds in a minute.

Hope this helped! :)

6 0

2 years ago

PLEASE ANSWER ASAP! NO SCAM LINKS OR REPORTED.

pochemuha

Answer:

Its A

Step-by-step explanation:

Standard equation: y=mx+b

x+y=0

-x -x

y=-x+0

8 0

3 years ago

Nate works at least 4 hours but not more than 9 hours. He earns $12.40 per hour. The function f(t) = 12.4t represents the amount

Mashcka [7]

The practical domain is all real numbers from 4 to 9, inclusive.

The practical range is all real numbers from 49.6 to 111.6, inclusive.

These are the correct options.

Explanation:

Given function is f(t) = 12.4t

Let us assume that Nate works 'x' hours so 4<x<9

And multiplying the hours with his earnings we get the range.

4*12.40=49.6 and 9*12.40=111.6. Let the amount earned be represented by y

Hence, domain can be represented as 4<x<9 and range can be represented as 49.6 < y < 111.6

7 0

2 years ago

Of interest is to test the hypothesis that the mean length of all face-to-face meetings and the mean length of all Zoom meetings

Goshia [24]

Answer:

Null hypothesis: $\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n$

Alternative hypothesis: $\mu_i \neq \mu_j , i,j =1,2,....,n$

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

Step-by-step explanation:

For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:

Null hypothesis: $\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n$

Alternative hypothesis: $\mu_i \neq \mu_j , i,j =1,2,....,n$

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

6 0

3 years ago

4/5 plus 3/4plus 7/10=? someone plz help

Readme [11.4K]

Answer:

it is 31/20 but in mixed form it's

$1 \times \frac{11}{20}$

5 0

2 years ago