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Makovka662 [10]
3 years ago
10

Which number forms a Pythagorean Triple with 8 and 10? A: 6 B: 15

Mathematics
2 answers:
daser333 [38]3 years ago
6 0
Are 6 and 15 the legs of the triangle?
laila [671]3 years ago
3 0
(8•8)+(6•6)=(10•10)
64+36=100
100=100
The answer is B
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The slope of the line below is 0.8. Write the equation of the line in point-slope
AlexFokin [52]

The equation of the line is y = 0.8x - 1.4 if the  slope of the line is 0.8 and line passes through coordinates (-2,-3)

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

The slope m = 0.8

The line passing through coordinates (-2,-3)

y = mx + c

y = 0.8x + c

Plug the point in the equation.

-3 = 0.8(-2) + c

c = -1.4

y = 0.8x - 1.4

Thus, the equation of the line is y = 0.8x - 1.4 if the  slope of the line is 0.8 and line passes through coordinates (-2,-3)

Learn more about the straight line here:

brainly.com/question/3493733

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4 0
2 years ago
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

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Step-by-step explanation:

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1/3 comes from how many times the line rises (1) and run (3)

Hope this helps!

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